Optimal. Leaf size=343 \[ \frac{3 i b \text{PolyLog}\left (2,-i e^{i \sin ^{-1}(c x)}\right ) \left (a+b \sin ^{-1}(c x)\right )}{4 c^5 d^3}-\frac{3 i b \text{PolyLog}\left (2,i e^{i \sin ^{-1}(c x)}\right ) \left (a+b \sin ^{-1}(c x)\right )}{4 c^5 d^3}-\frac{3 b^2 \text{PolyLog}\left (3,-i e^{i \sin ^{-1}(c x)}\right )}{4 c^5 d^3}+\frac{3 b^2 \text{PolyLog}\left (3,i e^{i \sin ^{-1}(c x)}\right )}{4 c^5 d^3}+\frac{x^3 \left (a+b \sin ^{-1}(c x)\right )^2}{4 c^2 d^3 \left (1-c^2 x^2\right )^2}-\frac{3 x \left (a+b \sin ^{-1}(c x)\right )^2}{8 c^4 d^3 \left (1-c^2 x^2\right )}+\frac{5 b \left (a+b \sin ^{-1}(c x)\right )}{4 c^5 d^3 \sqrt{1-c^2 x^2}}-\frac{b \left (a+b \sin ^{-1}(c x)\right )}{6 c^5 d^3 \left (1-c^2 x^2\right )^{3/2}}-\frac{3 i \tan ^{-1}\left (e^{i \sin ^{-1}(c x)}\right ) \left (a+b \sin ^{-1}(c x)\right )^2}{4 c^5 d^3}+\frac{b^2 x}{12 c^4 d^3 \left (1-c^2 x^2\right )}-\frac{7 b^2 \tanh ^{-1}(c x)}{6 c^5 d^3} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.536364, antiderivative size = 343, normalized size of antiderivative = 1., number of steps used = 16, number of rules used = 13, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.482, Rules used = {4703, 4657, 4181, 2531, 2282, 6589, 4677, 206, 266, 43, 4689, 12, 385} \[ \frac{3 i b \text{PolyLog}\left (2,-i e^{i \sin ^{-1}(c x)}\right ) \left (a+b \sin ^{-1}(c x)\right )}{4 c^5 d^3}-\frac{3 i b \text{PolyLog}\left (2,i e^{i \sin ^{-1}(c x)}\right ) \left (a+b \sin ^{-1}(c x)\right )}{4 c^5 d^3}-\frac{3 b^2 \text{PolyLog}\left (3,-i e^{i \sin ^{-1}(c x)}\right )}{4 c^5 d^3}+\frac{3 b^2 \text{PolyLog}\left (3,i e^{i \sin ^{-1}(c x)}\right )}{4 c^5 d^3}+\frac{x^3 \left (a+b \sin ^{-1}(c x)\right )^2}{4 c^2 d^3 \left (1-c^2 x^2\right )^2}-\frac{3 x \left (a+b \sin ^{-1}(c x)\right )^2}{8 c^4 d^3 \left (1-c^2 x^2\right )}+\frac{5 b \left (a+b \sin ^{-1}(c x)\right )}{4 c^5 d^3 \sqrt{1-c^2 x^2}}-\frac{b \left (a+b \sin ^{-1}(c x)\right )}{6 c^5 d^3 \left (1-c^2 x^2\right )^{3/2}}-\frac{3 i \tan ^{-1}\left (e^{i \sin ^{-1}(c x)}\right ) \left (a+b \sin ^{-1}(c x)\right )^2}{4 c^5 d^3}+\frac{b^2 x}{12 c^4 d^3 \left (1-c^2 x^2\right )}-\frac{7 b^2 \tanh ^{-1}(c x)}{6 c^5 d^3} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 4703
Rule 4657
Rule 4181
Rule 2531
Rule 2282
Rule 6589
Rule 4677
Rule 206
Rule 266
Rule 43
Rule 4689
Rule 12
Rule 385
Rubi steps
\begin{align*} \int \frac{x^4 \left (a+b \sin ^{-1}(c x)\right )^2}{\left (d-c^2 d x^2\right )^3} \, dx &=\frac{x^3 \left (a+b \sin ^{-1}(c x)\right )^2}{4 c^2 d^3 \left (1-c^2 x^2\right )^2}-\frac{b \int \frac{x^3 \left (a+b \sin ^{-1}(c x)\right )}{\left (1-c^2 x^2\right )^{5/2}} \, dx}{2 c d^3}-\frac{3 \int \frac{x^2 \left (a+b \sin ^{-1}(c x)\right )^2}{\left (d-c^2 d x^2\right )^2} \, dx}{4 c^2 d}\\ &=-\frac{b \left (a+b \sin ^{-1}(c x)\right )}{6 c^5 d^3 \left (1-c^2 x^2\right )^{3/2}}+\frac{b \left (a+b \sin ^{-1}(c x)\right )}{2 c^5 d^3 \sqrt{1-c^2 x^2}}+\frac{x^3 \left (a+b \sin ^{-1}(c x)\right )^2}{4 c^2 d^3 \left (1-c^2 x^2\right )^2}-\frac{3 x \left (a+b \sin ^{-1}(c x)\right )^2}{8 c^4 d^3 \left (1-c^2 x^2\right )}+\frac{b^2 \int \frac{-2+3 c^2 x^2}{3 c^4 \left (1-c^2 x^2\right )^2} \, dx}{2 d^3}+\frac{(3 b) \int \frac{x \left (a+b \sin ^{-1}(c x)\right )}{\left (1-c^2 x^2\right )^{3/2}} \, dx}{4 c^3 d^3}+\frac{3 \int \frac{\left (a+b \sin ^{-1}(c x)\right )^2}{d-c^2 d x^2} \, dx}{8 c^4 d^2}\\ &=-\frac{b \left (a+b \sin ^{-1}(c x)\right )}{6 c^5 d^3 \left (1-c^2 x^2\right )^{3/2}}+\frac{5 b \left (a+b \sin ^{-1}(c x)\right )}{4 c^5 d^3 \sqrt{1-c^2 x^2}}+\frac{x^3 \left (a+b \sin ^{-1}(c x)\right )^2}{4 c^2 d^3 \left (1-c^2 x^2\right )^2}-\frac{3 x \left (a+b \sin ^{-1}(c x)\right )^2}{8 c^4 d^3 \left (1-c^2 x^2\right )}+\frac{3 \operatorname{Subst}\left (\int (a+b x)^2 \sec (x) \, dx,x,\sin ^{-1}(c x)\right )}{8 c^5 d^3}+\frac{b^2 \int \frac{-2+3 c^2 x^2}{\left (1-c^2 x^2\right )^2} \, dx}{6 c^4 d^3}-\frac{\left (3 b^2\right ) \int \frac{1}{1-c^2 x^2} \, dx}{4 c^4 d^3}\\ &=\frac{b^2 x}{12 c^4 d^3 \left (1-c^2 x^2\right )}-\frac{b \left (a+b \sin ^{-1}(c x)\right )}{6 c^5 d^3 \left (1-c^2 x^2\right )^{3/2}}+\frac{5 b \left (a+b \sin ^{-1}(c x)\right )}{4 c^5 d^3 \sqrt{1-c^2 x^2}}+\frac{x^3 \left (a+b \sin ^{-1}(c x)\right )^2}{4 c^2 d^3 \left (1-c^2 x^2\right )^2}-\frac{3 x \left (a+b \sin ^{-1}(c x)\right )^2}{8 c^4 d^3 \left (1-c^2 x^2\right )}-\frac{3 i \left (a+b \sin ^{-1}(c x)\right )^2 \tan ^{-1}\left (e^{i \sin ^{-1}(c x)}\right )}{4 c^5 d^3}-\frac{3 b^2 \tanh ^{-1}(c x)}{4 c^5 d^3}-\frac{(3 b) \operatorname{Subst}\left (\int (a+b x) \log \left (1-i e^{i x}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{4 c^5 d^3}+\frac{(3 b) \operatorname{Subst}\left (\int (a+b x) \log \left (1+i e^{i x}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{4 c^5 d^3}-\frac{\left (5 b^2\right ) \int \frac{1}{1-c^2 x^2} \, dx}{12 c^4 d^3}\\ &=\frac{b^2 x}{12 c^4 d^3 \left (1-c^2 x^2\right )}-\frac{b \left (a+b \sin ^{-1}(c x)\right )}{6 c^5 d^3 \left (1-c^2 x^2\right )^{3/2}}+\frac{5 b \left (a+b \sin ^{-1}(c x)\right )}{4 c^5 d^3 \sqrt{1-c^2 x^2}}+\frac{x^3 \left (a+b \sin ^{-1}(c x)\right )^2}{4 c^2 d^3 \left (1-c^2 x^2\right )^2}-\frac{3 x \left (a+b \sin ^{-1}(c x)\right )^2}{8 c^4 d^3 \left (1-c^2 x^2\right )}-\frac{3 i \left (a+b \sin ^{-1}(c x)\right )^2 \tan ^{-1}\left (e^{i \sin ^{-1}(c x)}\right )}{4 c^5 d^3}-\frac{7 b^2 \tanh ^{-1}(c x)}{6 c^5 d^3}+\frac{3 i b \left (a+b \sin ^{-1}(c x)\right ) \text{Li}_2\left (-i e^{i \sin ^{-1}(c x)}\right )}{4 c^5 d^3}-\frac{3 i b \left (a+b \sin ^{-1}(c x)\right ) \text{Li}_2\left (i e^{i \sin ^{-1}(c x)}\right )}{4 c^5 d^3}-\frac{\left (3 i b^2\right ) \operatorname{Subst}\left (\int \text{Li}_2\left (-i e^{i x}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{4 c^5 d^3}+\frac{\left (3 i b^2\right ) \operatorname{Subst}\left (\int \text{Li}_2\left (i e^{i x}\right ) \, dx,x,\sin ^{-1}(c x)\right )}{4 c^5 d^3}\\ &=\frac{b^2 x}{12 c^4 d^3 \left (1-c^2 x^2\right )}-\frac{b \left (a+b \sin ^{-1}(c x)\right )}{6 c^5 d^3 \left (1-c^2 x^2\right )^{3/2}}+\frac{5 b \left (a+b \sin ^{-1}(c x)\right )}{4 c^5 d^3 \sqrt{1-c^2 x^2}}+\frac{x^3 \left (a+b \sin ^{-1}(c x)\right )^2}{4 c^2 d^3 \left (1-c^2 x^2\right )^2}-\frac{3 x \left (a+b \sin ^{-1}(c x)\right )^2}{8 c^4 d^3 \left (1-c^2 x^2\right )}-\frac{3 i \left (a+b \sin ^{-1}(c x)\right )^2 \tan ^{-1}\left (e^{i \sin ^{-1}(c x)}\right )}{4 c^5 d^3}-\frac{7 b^2 \tanh ^{-1}(c x)}{6 c^5 d^3}+\frac{3 i b \left (a+b \sin ^{-1}(c x)\right ) \text{Li}_2\left (-i e^{i \sin ^{-1}(c x)}\right )}{4 c^5 d^3}-\frac{3 i b \left (a+b \sin ^{-1}(c x)\right ) \text{Li}_2\left (i e^{i \sin ^{-1}(c x)}\right )}{4 c^5 d^3}-\frac{\left (3 b^2\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_2(-i x)}{x} \, dx,x,e^{i \sin ^{-1}(c x)}\right )}{4 c^5 d^3}+\frac{\left (3 b^2\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_2(i x)}{x} \, dx,x,e^{i \sin ^{-1}(c x)}\right )}{4 c^5 d^3}\\ &=\frac{b^2 x}{12 c^4 d^3 \left (1-c^2 x^2\right )}-\frac{b \left (a+b \sin ^{-1}(c x)\right )}{6 c^5 d^3 \left (1-c^2 x^2\right )^{3/2}}+\frac{5 b \left (a+b \sin ^{-1}(c x)\right )}{4 c^5 d^3 \sqrt{1-c^2 x^2}}+\frac{x^3 \left (a+b \sin ^{-1}(c x)\right )^2}{4 c^2 d^3 \left (1-c^2 x^2\right )^2}-\frac{3 x \left (a+b \sin ^{-1}(c x)\right )^2}{8 c^4 d^3 \left (1-c^2 x^2\right )}-\frac{3 i \left (a+b \sin ^{-1}(c x)\right )^2 \tan ^{-1}\left (e^{i \sin ^{-1}(c x)}\right )}{4 c^5 d^3}-\frac{7 b^2 \tanh ^{-1}(c x)}{6 c^5 d^3}+\frac{3 i b \left (a+b \sin ^{-1}(c x)\right ) \text{Li}_2\left (-i e^{i \sin ^{-1}(c x)}\right )}{4 c^5 d^3}-\frac{3 i b \left (a+b \sin ^{-1}(c x)\right ) \text{Li}_2\left (i e^{i \sin ^{-1}(c x)}\right )}{4 c^5 d^3}-\frac{3 b^2 \text{Li}_3\left (-i e^{i \sin ^{-1}(c x)}\right )}{4 c^5 d^3}+\frac{3 b^2 \text{Li}_3\left (i e^{i \sin ^{-1}(c x)}\right )}{4 c^5 d^3}\\ \end{align*}
Mathematica [A] time = 6.37722, size = 667, normalized size = 1.94 \[ \frac{18 a b \left (4 i \text{PolyLog}\left (2,-i e^{i \sin ^{-1}(c x)}\right )+i \sin ^{-1}(c x)^2+\sin ^{-1}(c x) \left (-4 \log \left (1+i e^{i \sin ^{-1}(c x)}\right )-3 i \pi \right )+2 \pi \left (-2 \log \left (1+e^{-i \sin ^{-1}(c x)}\right )+\log \left (1+i e^{i \sin ^{-1}(c x)}\right )+2 \log \left (\cos \left (\frac{1}{2} \sin ^{-1}(c x)\right )\right )-\log \left (-\cos \left (\frac{1}{4} \left (2 \sin ^{-1}(c x)+\pi \right )\right )\right )\right )\right )+18 a b \left (-4 i \text{PolyLog}\left (2,i e^{i \sin ^{-1}(c x)}\right )-i \sin ^{-1}(c x)^2+\sin ^{-1}(c x) \left (4 \log \left (1-i e^{i \sin ^{-1}(c x)}\right )+i \pi \right )+2 \pi \left (2 \log \left (1+e^{-i \sin ^{-1}(c x)}\right )+\log \left (1-i e^{i \sin ^{-1}(c x)}\right )-\log \left (\sin \left (\frac{1}{4} \left (2 \sin ^{-1}(c x)+\pi \right )\right )\right )-2 \log \left (\cos \left (\frac{1}{2} \sin ^{-1}(c x)\right )\right )\right )\right )+8 b^2 \left (9 i \sin ^{-1}(c x) \text{PolyLog}\left (2,-i e^{i \sin ^{-1}(c x)}\right )-9 i \sin ^{-1}(c x) \text{PolyLog}\left (2,i e^{i \sin ^{-1}(c x)}\right )-9 \text{PolyLog}\left (3,-i e^{i \sin ^{-1}(c x)}\right )+9 \text{PolyLog}\left (3,i e^{i \sin ^{-1}(c x)}\right )-14 \tanh ^{-1}(c x)-9 i \sin ^{-1}(c x)^2 \tan ^{-1}\left (e^{i \sin ^{-1}(c x)}\right )\right )+\frac{60 a^2 c x}{c^2 x^2-1}+\frac{24 a^2 c x}{\left (c^2 x^2-1\right )^2}-18 a^2 \log (1-c x)+18 a^2 \log (c x+1)-\frac{60 a b \left (\sqrt{1-c^2 x^2}-\sin ^{-1}(c x)\right )}{c x-1}+\frac{60 a b \left (\sqrt{1-c^2 x^2}+\sin ^{-1}(c x)\right )}{c x+1}+\frac{4 a b \left (\sqrt{1-c^2 x^2} (c x-2)+3 \sin ^{-1}(c x)\right )}{(c x-1)^2}-\frac{4 a b \left (\sqrt{1-c^2 x^2} (c x+2)+3 \sin ^{-1}(c x)\right )}{(c x+1)^2}+\frac{b^2 \left (\sin ^{-1}(c x) \left (74 \sqrt{1-c^2 x^2}+30 \cos \left (3 \sin ^{-1}(c x)\right )\right )+3 \left (3 c x-5 \sin \left (3 \sin ^{-1}(c x)\right )\right ) \sin ^{-1}(c x)^2+2 \left (c x+\sin \left (3 \sin ^{-1}(c x)\right )\right )\right )}{\left (c^2 x^2-1\right )^2}}{96 c^5 d^3} \]
Warning: Unable to verify antiderivative.
[In]
[Out]
________________________________________________________________________________________
Maple [B] time = 0.547, size = 903, normalized size = 2.6 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{16} \, a^{2}{\left (\frac{2 \,{\left (5 \, c^{2} x^{3} - 3 \, x\right )}}{c^{8} d^{3} x^{4} - 2 \, c^{6} d^{3} x^{2} + c^{4} d^{3}} + \frac{3 \, \log \left (c x + 1\right )}{c^{5} d^{3}} - \frac{3 \, \log \left (c x - 1\right )}{c^{5} d^{3}}\right )} + \frac{3 \,{\left (b^{2} c^{4} x^{4} - 2 \, b^{2} c^{2} x^{2} + b^{2}\right )} \arctan \left (c x, \sqrt{c x + 1} \sqrt{-c x + 1}\right )^{2} \log \left (c x + 1\right ) - 3 \,{\left (b^{2} c^{4} x^{4} - 2 \, b^{2} c^{2} x^{2} + b^{2}\right )} \arctan \left (c x, \sqrt{c x + 1} \sqrt{-c x + 1}\right )^{2} \log \left (-c x + 1\right ) + 2 \,{\left (5 \, b^{2} c^{3} x^{3} - 3 \, b^{2} c x\right )} \arctan \left (c x, \sqrt{c x + 1} \sqrt{-c x + 1}\right )^{2} - 2 \,{\left (c^{9} d^{3} x^{4} - 2 \, c^{7} d^{3} x^{2} + c^{5} d^{3}\right )} \int \frac{16 \, a b c^{4} x^{4} \arctan \left (c x, \sqrt{c x + 1} \sqrt{-c x + 1}\right ) -{\left (3 \,{\left (b^{2} c^{4} x^{4} - 2 \, b^{2} c^{2} x^{2} + b^{2}\right )} \arctan \left (c x, \sqrt{c x + 1} \sqrt{-c x + 1}\right ) \log \left (c x + 1\right ) - 3 \,{\left (b^{2} c^{4} x^{4} - 2 \, b^{2} c^{2} x^{2} + b^{2}\right )} \arctan \left (c x, \sqrt{c x + 1} \sqrt{-c x + 1}\right ) \log \left (-c x + 1\right ) + 2 \,{\left (5 \, b^{2} c^{3} x^{3} - 3 \, b^{2} c x\right )} \arctan \left (c x, \sqrt{c x + 1} \sqrt{-c x + 1}\right )\right )} \sqrt{c x + 1} \sqrt{-c x + 1}}{c^{10} d^{3} x^{6} - 3 \, c^{8} d^{3} x^{4} + 3 \, c^{6} d^{3} x^{2} - c^{4} d^{3}}\,{d x}}{16 \,{\left (c^{9} d^{3} x^{4} - 2 \, c^{7} d^{3} x^{2} + c^{5} d^{3}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{b^{2} x^{4} \arcsin \left (c x\right )^{2} + 2 \, a b x^{4} \arcsin \left (c x\right ) + a^{2} x^{4}}{c^{6} d^{3} x^{6} - 3 \, c^{4} d^{3} x^{4} + 3 \, c^{2} d^{3} x^{2} - d^{3}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} - \frac{\int \frac{a^{2} x^{4}}{c^{6} x^{6} - 3 c^{4} x^{4} + 3 c^{2} x^{2} - 1}\, dx + \int \frac{b^{2} x^{4} \operatorname{asin}^{2}{\left (c x \right )}}{c^{6} x^{6} - 3 c^{4} x^{4} + 3 c^{2} x^{2} - 1}\, dx + \int \frac{2 a b x^{4} \operatorname{asin}{\left (c x \right )}}{c^{6} x^{6} - 3 c^{4} x^{4} + 3 c^{2} x^{2} - 1}\, dx}{d^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]